Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Indefinite Integration

Question:

The value of $\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}}(x^3+x\, cos x+tan^5x)dx$ is :

Options:

0

1

2

$\pi $

Correct Answer:

0

Explanation:

$I=\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}}(x^3+x\, cos x+tan^5x)dx$

$=0$ (as for odd functions $\int\limits_{-a}^af(x)dx=0$)