The value of $\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}}(x^3+x\, cos x+tan^5x)dx$ is :
Answer & explanation
Correct answer: option 1
$I=\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}}(x^3+x\, cos x+tan^5x)dx$
$=0$ (as for odd functions $\int\limits_{-a}^af(x)dx=0$)