Match List-I with List-II
|
List-I Electrolytes |
List-II Examples |
|
(A) Non-electrolyte |
(I) Sucrose, Urea |
|
(B) Binary electrolyte |
(II) \( KCl, CH_3COOH \) |
|
(C) Quaternary electrolyte |
(III) \( H_2SO_4, BaCl_2 \) |
|
(D) Ternary electrolyte |
(IV) \( AlCl_3, K_3PO_4 \) |
Choose the correct answer from the options given below.
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → (A)-(I), (B)-(II), (C)-(IV), (D)-(III)
Electrolytes are named by the number of ions one formula unit gives on dissociation: binary (2 ions), ternary (3 ions) and quaternary (4 ions). A non-electrolyte does not dissociate at all. This number is also the ideal value of the van’t Hoff factor i.
(A) Non-electrolyte — This matches (I) Sucrose, Urea. Both dissolve as neutral molecules: 1 particle each, i = 1.
(B) Binary electrolyte — This matches (II) \(KCl, CH_3COOH\). Each gives two ions (acetic acid only partly, being a weak acid):
\( \displaystyle \ce{KCl -> K+ + Cl-} \qquad \ce{CH3COOH <=> CH3COO- + H+} \)
(C) Quaternary electrolyte — This matches (IV) \(AlCl_3, K_3PO_4\). Each gives four ions, 1 + 3 = 4:
\( \displaystyle \ce{AlCl3 -> Al^3+ + 3Cl-} \qquad \ce{K3PO4 -> 3K+ + PO4^3-} \)
(D) Ternary electrolyte — This matches (III) \(H_2SO_4, BaCl_2\). Each gives three ions, 2 + 1 = 3:
\( \displaystyle \ce{H2SO4 -> 2H+ + SO4^2-} \qquad \ce{BaCl2 -> Ba^2+ + 2Cl-} \)
Shortcut: (C)-(IV) appears only in Option (3).