In a circle, two equal and parallel chords are 6 cm apart and they lie on the opposite sides of the centre of the circle, whose radius is 5 cm. The length of each chord (in cm), is:
Answer & explanation
Correct answer: option 3
We have,
Distance between two equal chords = 6 cm
Radius of circle = 5 cm
Now, we know that,
ΔOBM ≅ ΔODN
So, OM = ON = 6/2 = 3 cm
We know that,
MB2 + OM2 = OB2
= MB2 + 32 = 52
= MB2 = 25 - 9 = 16
= MB = 4 cm
AM = 2MB
= 2 × 4 = 8