Practicing Success
Find the projection of the vector (\(\hat{i}\)- \(\hat{j}\)) on the vector (\(\hat{i}\)+ \(\hat{j}\)). |
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Let \(\vec{a}\)= (\(\hat{i}\)- \(\hat{j}\)) and \(\vec{b}\) = (\(\hat{i}\)+ \(\hat{j}\)) Now, projection of \(\vec{a}\) on \(\vec{b}\) is given by, (\(\vec{a}\).\(\vec{b}\))/|\(\vec{b}\)| = {1.1 + (-1).1}/√(1+1) = 0 Hence, the projection of vector (\(\hat{i}\)- \(\hat{j}\)) on the vector (\(\hat{i}\)+ \(\hat{j}\)) is 0.
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