At 10°C the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110°C this ratio is :
Answer & explanation
Correct answer: option 1
PV = nRT
⇒ \(P\frac{m}{\rho} = \frac{m}{M}RT\)
⇒ \(\frac{(\frac{\rho}{P})_f}{(\frac{\rho}{P})_i} = \frac{T_i}{T_f} = \frac{10 + 273}{110 + 273} = \frac{283}{383}\)
⇒ \(\frac{(\frac{\rho}{P})_f}{X} = \frac{283}{383}\)
∴\((\frac{\rho}{P})_f = \frac{283}{383} X\)