What is the work done in moving a $δq$ charge from A to B? |
0 $\frac{kqδq}{r}$ $\frac{kqδq}{\sqrt{2r}}$ $\frac{2kq}{r}$ |
0 |
The correct answer is Option (1) → 0 As the circle which is enclosing the +q charge at the center form an equipotential surface. ∴ No work is needed in moving the charge for A to B. |