The value of $\sqrt{3\frac{1}{16}} + \frac{1}{2} - \frac{3}{4} = $

$1\frac{3}{4}$ 1 $1\frac{1}{2}$ $1\frac{1}{4}$

$1\frac{1}{2}$

$\sqrt{3\frac{1}{16}} + \frac{1}{2} - \frac{3}{4}$ = $\sqrt{\frac{49}{16}} + \frac{1}{2} - \frac{3}{4}$ = $\frac{7}{4} - \frac{1}{4}$ = $\frac{7}{4} - \frac{1}{4}$ = $\frac{6}{4}$ = $1\frac{1}{2}$