Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Moving Charges and Magnetism

Question:

An electric field of intensity 6×10V/m is applied perpendicular to the direction of motion of the electron. A magnetic field of intensity 8×10−2wb/m2 is applied perpendicular to both the electric field and direction of motion of the electron. What is the velocity of the electron if it passes undeflected?

Options:

7.5×10-5m/s

7.5×105m/s

14 ×105m/s

3×108m/s

Correct Answer:

7.5×105m/s

Explanation:

For undeflected, Electric force = Magnetic Force.

so, qE = qvB

s0, E = vB