If a person travels at a speed of 56 km/h, he will reach his destination on time. He covers \(\frac{3}{4}\)th of his journey in \(\frac{3}{7}\)th of time. At what speed (in km/h) should he travel to cover the remaining distance to reach his destination on time?
Answer & explanation
Correct answer: option 1
D = S × T
Let, Time is 7 hours
Distance = 56 × 7 = 392,
Here, He covers \(\frac{3}{4}\)th of his journey in \(\frac{3}{7}\)th of time
Now, We have to find the speed to cover the remaining \(\frac{1}{4}\)th journey in \(\frac{4}{7}\)th of the time.
Therefore,
Speed Time Distance
56 7 392
↓ ↓
×\(\frac{4}{7}\) ×\(\frac{1}{4}\)
↓ ↓
4 98
Speed for remaining journey = \(\frac{98}{4}\) = 24.5 km/h