Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Wave Optics

Question:

Intensity of central bright fringe due to interference of two identical coherent monochromatic sources is I. If one of the source is switched off, then intensity of central bright fringe becomes     

Options:

$\frac{I}{2}$

$\frac{I}{3}$

$\frac{I}{4}$

Correct Answer:

$\frac{I}{4}$

Explanation:

Let Intensity due to any one source is $I_1$.

Intensity of the bright fringe is $I = 4I_1$

When one of the source is switched off then intensity is $I_1 = \frac{I}{4}$