In an LPP, with the constraints are x - 3y ≥ 0, y ≥ 0, 0 ≤ x ≤ 3. The feasible region is : 

bounded and lies in the first quadrant.

Given constraints

$x-3y \ge 0$

$y \ge 0$

$0 \le x \le 3$

From $x-3y \ge 0$

$x \ge 3y$

Since $y \ge 0$ and $x \ge 0$, the feasible region lies in the first quadrant.

Also $0 \le x \le 3$ restricts the region between $x=0$ and $x=3$.

Thus the feasible region is limited (finite) and lies entirely in the first quadrant.

The feasible region is bounded and lies in the first quadrant.