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Calculate the molarity of a solution containing 5g of NaOH in 450 mL solution. |
\(0.278 × 10^{-3} M\) \(0.278 M\) \(2.78 × 10^{-3} M\) \(2.78 M\) |
\(0.278 M\) |
Given, Mass of NaOH = 5g Volume of the solution = \(450 mL\) =\(450 × 10^{-3}L\) Molar mass of NaOH = \(23 + 16 + 1 = 40 \text{ g mol}^{-1}\) Moles of NaOH = \(\frac{\text{mass of NaOH}}{\text{molar mass of NaOH}}\) moles of NaOH = \(\frac{5 \text{g}}{40} { g mol}^{-1} = 0.125 mol\) Molarity of the solution =\(\frac{\text{Moles of solute}}{\text{Volume of solution (L)}}\) Molarity of the solution =\{\frac{0.125 mol}{450 × 10^{-3}}\} = \(0.278 \text{ mol L}^{-1}\) or \(0.278 M\) |