(1+ cos ∝) (1 - sin β) ( 1 + cos y) ( 1 - sin δ) ( 1 - cos b) = ( 1 - cos ∝) ( 1 + sin β) ( 1 - cos y) ( 1 + sin δ). ( 1 + cos b), find value of each term.
Answer & explanation
Correct answer: option 1
Let ( 1+cos ∝ ) ( 1- sin β ) ( 1+ cos y) ( 1- sin δ ) ( 1- cos b ) = K
( 1- cos ∝ ) ( 1+ sin β ) ( 1- cos y) ( 1+ sin δ ) ( 1+ cos b ) = K
Now,
K.K = ( 1+cos ∝ )( 1- cos ∝ )( 1- sin β )( 1+ sin β )( 1+ cos y)( 1- cos y)( 1- sin δ )( 1+ sin δ ) ( 1- cos b )( 1+ cos b )
K2 = sin2 ∝ cos2 β sin2 y cos2 δ sin2 b
K = ± ( sin ∝ cos β sin y cos δ sin b)