Practicing Success
Practicing Success
CUET Preparation Today
If $4 sin^{-1} x + cos^{-1}x = \pi , $ then x equals |
$\frac{1}{2}$ $\frac{\sqrt{3}}{2}$ $-\frac{1}{2}$ none of these |
$\frac{1}{2}$ |
We have, $4 sin^{-1} x + cos^{-1}x = \pi $ $ ⇒ 4sin^{-1}x +\frac{\pi}{2}- sin^{-1}x = \pi $ $⇒3sin^{-1}x=\frac{\pi}{2}⇒ x = sin \left(\frac{\pi}{6}\right) =\frac{1}{2}$ |
