Practicing Success
(a + b − c + d)2 - (a − b + c − d)2 = ? |
4a(b + d - c) 2a(a + b - c) 2a(b + c - d) 4a(b - d + c) |
4a(b + d - c) |
Given, (a + b – c + d)2 – (a – b + c – d)2 Put a = 1, b = 2, c = 3 and d = 4 and satisfy from the options, = (1 + 2 – 3 + 4)2 – (1 – 2 + 3 – 4)2 = 16 – 4 = 12 If we check option 2 = 4a (b + d – c) = 4 × 1 (2 + 4 – 3) = 4 × 3 = 12 (satisfied) So the answer is = 4a (b + d – c) |