The side BC of a triangle ABC is extended to the point D. If ∠ACD = 132° and ∠B=$\frac{4}{7}$ ∠A, then the measure of ∠A is equal to:

60° 80° 50° 84°

84°

The angle made by straight line = 180°  So,  BCD forms a straight line ∠BCA = 180° – 132° = 48°  Now, Sum of all angles of a triangle = 180°   ∠B + ∠C + ∠A = 180°  (4/7) × ∠A + ∠A = 180° – 48°  (11/7) × ∠A = 132°   ∠A = 84°