Match List I with List II
| List I | List II |
| A. Linear plot with +ve slope and an intercept | I. \(t_{1/2}\) vs \(\frac{1}{[A]_0}\) for 2nd order |
| B. Linear plot with -ve slope and an intercept | II. \(t_{1/2}\) vs \([A]_0\) for 1st order |
| C. Linear horizontal plot | III. \(\frac{1}{[A]}\) vs time for the 2nd order |
| D. Linear plot passing through the origin | IV. Conc. \([A]\) vs time for zero order |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → A-III, B-IV, C-II, D-I
(A) Linear plot with +ve slope and an intercept — (III) 1/[A] vs time for 2nd order. For a second order reaction 1/[A] = kt + 1/[A]0: slope = +k, intercept = 1/[A]0.
(B) Linear plot with −ve slope and an intercept — (IV) [A] vs time for zero order. For a zero order reaction [A] = −kt + [A]0: slope = −k, intercept = [A]0.
(C) Linear horizontal plot — (II) t1/2 vs [A]0 for 1st order. t1/2 = 0.693/k does not depend on [A]0, so the line is parallel to the x-axis.
(D) Linear plot passing through the origin — (I) t1/2 vs 1/[A]0 for 2nd order. t1/2 = 1/(k[A]0), so t1/2 is directly proportional to 1/[A]0.