Let A and B be independent events such that P(A) = 0.3 and P(B) = 0.4, then Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(I), (B)-(II), (C)-(III), (D)-(IV) (A)-(II), (B)-(I), (C)-(IV), (D)-(III) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) (A)-(IV), (B)-(I), (C)-(III), (D)-(II) |
(A)-(III), (B)-(IV), (C)-(I), (D)-(II) |
The correct answer is Option (3) → (A)-(III), (B)-(IV), (C)-(I), (D)-(II) Given:
Calculations: (A) $P(A \cap B) = P(A) \cdot P(B) = 0.3 \cdot 0.4 = 0.12$ (B) $P(A \cup B) = P(A) + P(B) - P(A \cap B) = 0.3 + 0.4 - 0.12 = 0.58$ (C) $P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{0.12}{0.4} = 0.3$ (D) $P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.12}{0.3} = 0.4$ Matching:
|