Practicing Success
Practicing Success
CUET Preparation Today
The dimensions of universal gravitational constant are |
$M^{–2}L^2T^{–2}$ $M^{–1}L^3T^{–2}$ $ML^{–1}T^{–2}$ $ML^2T^{–2}$ |
$M^{–1}L^3T^{–2}$ |
The correct answer is Option (2) → $M^{–1}L^3T^{–2}$ $F=G\frac{m_1m_2}{r^2}$ $∴G=\frac{Fr^2}{m_1m_2}=M^{–1}L^3T^{–2}$ |
