The dimensions of universal gravitational constant are
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $M^{–1}L^3T^{–2}$
$F=G\frac{m_1m_2}{r^2}$
$∴G=\frac{Fr^2}{m_1m_2}=M^{–1}L^3T^{–2}$
The dimensions of universal gravitational constant are
Correct answer: option 2
The correct answer is Option (2) → $M^{–1}L^3T^{–2}$
$F=G\frac{m_1m_2}{r^2}$
$∴G=\frac{Fr^2}{m_1m_2}=M^{–1}L^3T^{–2}$