Practicing Success
Practicing Success
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$\lim\limits_{x \rightarrow 0}\left(\frac{\sin \left(\pi \cos ^2 x\right)}{x^2}\right)$ equals |
$-\pi$ $\pi$ $\frac{\pi}{2}$ 1 |
$\pi$ |
$\lim\limits_{x \rightarrow 0} \frac{\sin (\pi(1-(\sin x)^2))}{x^2}$ $=\lim\limits_{x \rightarrow 0} \frac{\pi \sin \pi \sin ^2 x}{\pi \sin ^2 x} . \frac{\sin ^2 x}{x^2}$ $=\pi$ Hence (2) is the correct answer. |
