What is the area (in m² ), up to 1 place of decimal) of an equilateral triangular field of sides 8.5 m?

$181.1\sqrt{3}$

We already know that,

Area of a equilateral triangle = area = \(\frac{\sqrt {3}}{4}\) × (side)²

Length of side of an equilateral triangle = 8.5 m.

Area of a equilateral triangle = area = \(\frac{\sqrt {3}}{4}\) × (8.5)²

= \(\frac{\sqrt {3}}{4}\) 72.25

= $\sqrt {3}$ × (18.06) = 18.1$\sqrt {3}$