What is the area (in m2 ), up to 1 place of decimal) of an equilateral triangular field of sides 8.5 m?
Answer & explanation
Correct answer: option 2
We already know that,
Area of a equilateral triangle = area = \(\frac{\sqrt {3}}{4}\) × (side)2
Length of side of an equilateral triangle = 8.5 m.
Area of a equilateral triangle = area = \(\frac{\sqrt {3}}{4}\) × (8.5)2
= \(\frac{\sqrt {3}}{4}\) 72.25
= $\sqrt {3}$ × (18.06) = 18.1$\sqrt {3}$