CUET Preparation Today
If x and y be the distances of the object and image formed by a concave mirror from its focus and f be the focal length then |
xf = y2 xy = f2 x/y = f x/y = f2 |
xy = f2 |
According to Newton's formula xy = f2 Note that $m=\frac{f}{f-u}=\frac{f-v}{f}$ or $\frac{f}{x}=\frac{y}{x} \quad \Rightarrow \quad x y=f^2$ |
