If a, b and c are the median, mode and range, respectively of the dat…

Arrange in as Ascending order = 4, 5,5, 5, 6, 6, 7, 9, 10, 10, 11, 12, 14, 20

 N = 14 which is even

Hence, median (a) = \(\frac{(\frac{n}{2})th\;term\;+\;(\frac{n}{2} +1)th\;term}{2}\) 

                        = \(\frac{7th\;term\;+\;8th\;term}{2}\) 

                       = \(\frac{7+9}{2}\)   = 16

Mode  = is most frequently occurring value in the list. 

i.e.  Mode (b) = 5

Range is the difference between the largest number and smallest number of data.

i.e.  Range (c)= 20 - 4 = 16

Now, (3a-2b+c) = 3 ×8 - 2×5 + 16 = 30