If A and B are arbitrary events, then
Answer & explanation
Correct answer: option 2
We have,
$P(A ∪ B) =P(A) +P(B) - P(A ∩ B)$
$ ⇒ P(A ∪ B) ≤ P(A) +P(B)$
If A and B are arbitrary events, then
Correct answer: option 2
We have,
$P(A ∪ B) =P(A) +P(B) - P(A ∩ B)$
$ ⇒ P(A ∪ B) ≤ P(A) +P(B)$