Find the value of (\(\frac{sin 27°}{cos 63°}\))2 + (\(\frac{cos 63°}{sin 27°}\))2
Answer & explanation
Correct answer: option 2
(\(\frac{sin 27°}{cos 63°}\))2 + (\(\frac{cos 63°}{sin 27°}\))2
⇒ (\(\frac{sin 27°}{sin (90°-27°)}\))2 + (\(\frac{cos 63°}{cos (90°-63°)}\))2
⇒ (\(\frac{sin 27°}{sin 27°}\))2 + (\(\frac{cos 63°}{cos 63°}\))2
⇒ 1 + 1 = 2