Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

Case: Read the passage and answer the following question(s).

Two spherical cavities (A and B) of radii y and x respectively are hollowed out from the interior of a conducting sphere of radius R. Charges q1 and q2 are placed at center of cavities A and B. The situation is depicted in the figure given:

If the potential of the conductor is 1 V, what is the potential at an arbitrary point P at the distance r from the center of the cavity A (r < y) ?

Options:

q1/(4πεo ) [1/x - 1/r ]

1+ q1/(4πεo ) [1/x - 1/r ]

1- q1/(4πεo ) [q2/r - q1/x ]

1+ 1/(4πεo ) [q1/r - q2/y ]

Correct Answer:

1+ 1/(4πεo ) [q1/r - q2/y ]

Explanation:

Potential at point P = Potential of the conductor + Potential due to charge q1 at center + Potential due to induced charges at inner surface