The standard electrode potential for Daniell cell is 1.1 V. The standard Gibbs free energy for the reaction $Zn(s) + Cu^{2+}(aq) →Zn^{2+}(aq)+Cu(s)$ is approximately: |
$-212.27J/mol$ $- 21.22 J/mol$ $-212271.4 J/mol$ $-2.1227 J/mol$ |
$-212271.4 J/mol$ |
The correct answer is Option (3) → $-212271.4 J/mol$ |