A man reaches his destination 32 minutes late if he moves by 6 km/h and reaches 18 minutes early if speed is 7 km/h.  Find thrice the distance b/w his destination from the starting point?

105 km

Speed    →  6     :     7

time      →  7     :     6

                   ↓           ↓   (Diff. 1)  → (32 + 18) = 50

                 ×50         

                   ↓       

               350 min

D = s × t

D = 6 ×\(\frac{350}{60}\) = 35 km

Thrice of distance = 35 × 3 = 105 km