A man reaches his destination 32 minutes late if he moves by 6 km/h and reaches 18 minutes early if speed is 7 km/h. Find thrice the distance b/w his destination from the starting point?
Answer & explanation
Correct answer: option 2
Speed → 6 : 7
time → 7 : 6
↓ ↓ (Diff. 1) → (32 + 18) = 50
×50
↓
350 min
D = s × t
D = 6 ×\(\frac{350}{60}\) = 35 km
Thrice of distance = 35 × 3 = 105 km