Practicing Success
In Young's double slit experiment using monochromatic light of wavelength $\lambda$, the intensity of light at a point on the screen where path difference $\lambda$ is $\mathrm{K}$ units. What is the intensity of light at a point where path difference is $\frac{\lambda}{3} ?$ |
\(\frac{K}{6}\) \(\frac{K}{4}\) \(\frac{K}{2}\) \(\frac{K}{8}\) |
\(\frac{K}{4}\) |
$\text{ Let two intensities are equal to I , When path difference between waves is λ , the two waves are in phase}$ $ \text{Resultant Intensity is }I_R = I_1 + I_2 + 2\sqrt{I_1 I_2}cos\phi$ $\text{ path difference is λ hence phase difference is }2\pi$ $\Rightarrow I_R = I_1 + I_2 + 2\sqrt{I_1 I_2} = (\sqrt{I_1} + \sqrt{I_2})^2$ $\Rightarrow K = (\sqrt I + \sqrt I)^2 = 4I$ when path difference is $\frac{\lambda}{3}$ then phase difference is $\frac{2\pi}{3}$ $I'= I + I + 2 I cos \frac{2\pi}{3} = I = \frac{K}{4}$ |