Target Exam

CUET

Subject

Chemistry

Chapter

Physical: Solutions

Question:

The increasing order of osmotic pressure of 0.1 M aqueous solution of the following is:

(A) $MgCl_2$
(B) $NaCl$
(C) $NH_2CONH_2$
(D) $K_3[Fe(CN)_6]$

Choose the correct answer from the options given below:

Options:

(A), (B), (D), (C)

(A), (B), (C), (D)

(C), (B), (A), (D)

(D), (A), (B), (C)

Correct Answer:

(C), (B), (A), (D)

Explanation:

The correct answer is Option (3) → (C), (B), (A), (D)

To determine the increasing order of osmotic pressure for these 0.1 M aqueous solutions, we use the formula for osmotic pressure ($\pi$):

$\pi = iCRT$

Since the molarity ($C = 0.1\text{ M}$), gas constant ($R$), and temperature ($T$) are the same for all solutions, the osmotic pressure depends entirely on the van't Hoff factor ($i$), which represents the number of particles the solute dissociates into.

Calculating the van't Hoff factor ($i$):

  • (C) $NH_2CONH_2$ (Urea): This is a non-electrolyte. It does not dissociate in water, so $i = 1$.
  • (B) $NaCl$ (Sodium Chloride): This salt dissociates into two ions: $Na^+$ and $Cl^-$. Thus, $i = 2$.
  • (A) $MgCl_2$ (Magnesium Chloride): This salt dissociates into three ions: $Mg^{2+}$ and $2Cl^-$. Thus, $i = 3$.
  • (D) $K_3[Fe(CN)_6]$ (Potassium Ferricyanide): This complex salt dissociates into four ions: $3K^+$ ions and $1[Fe(CN)_6]^{3-}$ complex ion. Thus, $i = 4$.