If $f(x)=\frac{x^{10}}{10}+\frac{x^9}{9}+............+\frac{x^2}{2}+x+1$ then the value of $f'(0)$ is :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 1
$f(x)=\frac{x^{10}}{10}+\frac{x^9}{9}+............+\frac{x^2}{2}+x+1$
$f'(x)=x^9+x^8+.........+x+1$
$⇒f'(0)=1$