Practicing Success
Let $\triangle \mathrm{ABC} \sim \triangle \mathrm{RPQ}$ and $\frac{{ar}(\triangle A B C)}{{ar}(\triangle P Q R)}=\frac{16}{25}$. If $\mathrm{PQ}=4 \mathrm{~cm}, \mathrm{QR}=6 \mathrm{~cm}$ and $\mathrm{PR}=7 \mathrm{~cm}$, then $\mathrm{AC}($ in $\mathrm{cm})$ is equal to: |
6 4.8 3.6 7.2 |
4.8 |
\(\frac{ae(ABC)}{ar(RPQ)}\) = \(\frac{16}{25}\) Now, According to the question, \(\frac{ae(ABC)}{ar(RPQ)}\) = \( {AC }^{ 2} \)/\( {QR }^{ 2} \) = \(\frac{16}{25}\) = \( {AC }^{ 2} \)/\( {6 }^{ 2} \) = 25\( {AC }^{ 2} \) = 36 x 16 = AC = \(\frac{24}{5}\) = AC = 4.8 cm Therefore, AC Is 4.8 cm. |