Solution of $\cos x\frac{dy}{dx}+y\sin x = 1$ is:
Answer & explanation
Correct answer: option 2
$\frac{dy}{dx}+y\tan x=\sec x;I.F.=e^{\int\tan xdx}=e^{\log \sec x}=\sec x$
$y\sec x=\int\sec^2 xdx$ ⇒ y sec x = tan x + c
Solution of $\cos x\frac{dy}{dx}+y\sin x = 1$ is:
Correct answer: option 2
$\frac{dy}{dx}+y\tan x=\sec x;I.F.=e^{\int\tan xdx}=e^{\log \sec x}=\sec x$
$y\sec x=\int\sec^2 xdx$ ⇒ y sec x = tan x + c