If $I_{0}$ is the intensity of the central diffraction band in the single slit diffraction experiment, then the intensity of the band when the slit width is doubled will be:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $4 I_{0}$
The intensity of the central diffraction band is proportional to the square of slit width -
$I_0∝a^2$
if slit width is doubled $(a'=2a)$
$I'∝(2a)^2=4a^2$
$∴I'=4I_0$