Practicing Success
If (x + 1) (y + 1) (y + x) + xy = 0 x + y ≠ -xy Find the value of (x + y + 4)2 |
0 16 9 25 |
9 |
(x + 1) (y + 1) (y + x) + xy = 0 ..... (i) if x + y ≠ -xy it means (x + y + xy) is one of the root of the given equation (i) So, (x + 1) (y + 1) (y + x) + xy = 0 (xy + y + x + 1) (y + x) + xy = 0 xy (y + x) + (y + x + 1)(y + x) + xy = 0 xy (y + x + 1) + (y + x + 1)(y + x) = 0 (y + x + 1)(xy + y + x) = 0 (x + y + xy) (x + y + 1) = 0 So, x + y + 1 = 0 and x + y = -1 Put in (x + y + 4)2 ⇒ (-1 + 4)2 = 9 |