Practicing Success
A system consists of three masses m1, m2 and m3 connected by a string passing over a pulley P. The mass m1 hangs freely and m2 and m3 are on a rough horizontal table (the coefficient of friction = µ). The pulley is frictionless and of negligible mass. The downward acceleration of mass m1 is (Assume m1 = m2 = m3 = m) |
\(\frac{g(1-2\mu)}{9}\) \(\frac{2g\mu)}{3}\) \(\frac{g(1-2\mu)}{3}\) \(\frac{g(1-2\mu)}{2}\) |
\(\frac{g(1-2\mu)}{3}\) |
\( m_1g - T_1 = m_1a \) ---------(1) \( T_1 - f_1 - T_2 = m_2a \) ------------(2) \( T_3 - f_1 = m_3a \) -----------(3) On solving above equation we get m1 = m2 = m3 = m mg - 2μmg = 3ma ⇒ a = \(\frac{g(1-2\mu)}{3}\) |