Practicing Success
If $2\sin θ-1=0$, then find the value of $2\cos^2θ-\sin^3θ$. |
0 $\frac{3}{2}$ $\frac{11}{8}$ 1 |
$\frac{11}{8}$ |
sin θ = \(\frac{1}{2}\) = sin 30º So, θ = 30º Now, $2\cos^2θ-\sin^3θ$ = $2\cos^230º-\sin^330º$ = 2 × \(\frac{3}{4}\) - \(\frac{1}{8}\) = \(\frac{3}{2}\) - \(\frac{1}{8}\) = \(\frac{12 - 1}{8}\) = \(\frac{11}{8}\) The correct answer is Option (3) → \(\frac{11}{8}\) |