Practicing Success
Ramu works 4 times as fast as Somu. If Somu can complete a work in 20 days independently, then the number of days in which Ramu and Somu together can complete the work is: |
5 days 4 days 6 days 3 days |
4 days |
According to the question, Ramu works 4 times as fast as Somu, therefore, Ramu : Somu = 4 : 1 (Efficiency) ⇒ Somu completes a work in 20 days, ⇒ Total work = 1 x 20 = 20 units ..(Efficiency × Days = Total work) ⇒ Time required by Ramu and Somu to complete the work together = \(\frac{20}{4+1}\) = \(\frac{20}{5}\) = 4 days, ..(\(\frac{Work}{Efficiency}\) = Time) |