If all the elements of \(3\times 3\) matrix \(A\) are \(1\), then \(A^2-3A\) is
Answer & explanation
Correct answer: option 1
$A=\begin{bmatrix}1&1&1\\1&1&1\\1&1&1\end{bmatrix}$
$A^2=\begin{bmatrix}3&3&3\\3&3&3\\3&3&3\end{bmatrix}$
so $A^2=3A$
$⇒A^2-3A=0$