If 5 sinθ = 7 cosθ . Then find the value of cosecθ .

5 sinθ = 7 cosθ

tanθ = \(\frac{7}{5}\)  (where 7 → P and 5 → B)

H = \(\sqrt {(7)^2 + (5)^2}\)

H = \(\sqrt {49 + 25}\) = \(\sqrt {74}\)

cosecθ = \(\frac{H}{P}\) =  \(\frac{\sqrt {74}}{7}\)