If the three sides of a triangle are 11 cm, 12 cm and 13 cm, then whatis the area of the given triangle (in cm2)?
Answer & explanation
Correct answer: option 3
We know that,
Area of a triangle = \(\sqrt {s(s-a)(s-b)(s-c) }\)
and semi perimeter = \(\frac{a + b + c}{2}\)
The three sides of a triangle are 11 cm, 12 cm and 13 cm,
So according to the question,
semi perimeter = \(\frac{11 + 12 + 13}{2}\) = 18cm
Area of triangle = \(\sqrt {18(18-11)(18-12)(18-13) }\)
= \(\sqrt {18(7)(6)(5) }\)
= \(\sqrt {18(210) }\)
= \(\sqrt {3780 }\) = $6\sqrt{105}$