Target Exam

CUET

Subject

Chemistry

Chapter

Physical: Solutions

Question:

Match List I with List II:

List I

\(K_H \text{ values }/ K\text{ bar}\)

List II

Gas

(A) 145 (I) \(CO_2\)
(B) 89 (II) \(He\)
(C) 76.5 (III) \(N_2\) (at 293 K)
(D) 1.67 (IV) \(N_2\) (at 303 K)

Choose the correct answer from the options given below:

Options:

(A)-(II), (B)-(IV), (C)-(III) D-(I)

(A)-(I), (B)-(II), (C)-(III) D-(IV)

(A)-(II), (B)-(III), (C)-(IV) D-(I)

(A)-(I), (B)-(III), (C)-(II) D-(IV)

Correct Answer:

(A)-(II), (B)-(IV), (C)-(III) D-(I)

Explanation:

The correct answer is option 1. (A)-(II), (B)-(IV), (C)-(III) D-(I).

List I

\(K_H \text{ values }/ K\text{ bar}\)

List II

Gas

(A) 145 (II) \(He\)
(B) 89 (IV) \(N_2\) (at 303 K)
(C) 76.5 (III) \(N_2\) (at 293 K)
(D) 1.67 (I) \(CO_2\)

Henry's law constant $K_H$ is higher for gases that are less soluble in a liquid.

  • He (helium) is least soluble $\Rightarrow$ highest $K_H \Rightarrow$ matches 145 $\rightarrow$ (A)-(II)
  • For the same gas, increase in temperature decreases solubility, so $K_H$ increases

$\Rightarrow K_H$ of $N_2$ at $303\text{ K} > 293\text{ K}$

$\Rightarrow 89 \rightarrow N_2 (303\text{ K}) \Rightarrow$ (B)-(IV)

$\Rightarrow 76.5 \rightarrow N_2 (293\text{ K}) \Rightarrow$ (C)-(III)

  • $CO_2$ is most soluble $\Rightarrow$ lowest $K_H$ $\Rightarrow 1.67 \rightarrow$ (D)-(I)

Thus, the correct matching is: (A)-(II), (B)-(IV), (C)-(III), (D)-(I)