In a circle with centre at O and radius 8 cm, AB is a chord of length 14 cm. If OM is perpendicular to AB, then the length of OM is :
Answer & explanation
Correct answer: option 4
Radius of circle = 8 cm
AM = MB = \(\frac{14}{2}\) = 7 cm
By using pythagoras theorem,
AO² = AM² + OM²
8² = 7² + OM²
OM² = 64 - 49
OM² = 15
OM = √15 cm