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In a circle with centre at O and radius 8 cm, AB is a chord of length 14 cm. If OM is perpendicular to AB, then the length of OM is : |
$\sqrt{10}$ cm $\sqrt{5}$ cm $\sqrt{12}$ cm $\sqrt{15}$ cm |
$\sqrt{15}$ cm |
Radius of circle = 8 cm AM = MB = \(\frac{14}{2}\) = 7 cm By using pythagoras theorem, AO² = AM² + OM² 8² = 7² + OM² OM² = 64 - 49 OM² = 15 OM = √15 cm |
