The charge flowing across the cell on closing the key k is equal to
Answer & explanation
Correct answer: option 2
When the key is kept open, the charge drawn from the source is
Q = CeqV = $\frac{C}{2}$V
When the key is closed the capacitor 2 gets short circuited
And C'eq = C
∴ Q' = CV
charge flown through cell Q' - Q = $\frac{C}{2}$V
∴ (B) is correct choice.