If 2x = 4y = 8z and xyz = 288, then find the value of x. |
4 6 8 12 |
12 |
(2)x = ((2)2)y = ((2)3)z 2x = 22y = 23z So, in this condition, if base is same, then power will be equal x = 2y = 3z x = 6R y = 3R z = 2R Now, xyz = 288 6R×3R×2R = 288 36R3 = 288 R3 = 8 R = 2 x =6×2 = 12 |