Match List-I with List-II with the corresponding boiling points.
Choose the correct answer from the options given below: |
(A)-(III), (B)-(IV), (C)-(I), (D)-(II) (A)-(II), (B)-(IV), (C)-(I), (D)-(III) (A)-(III), (B)-(I), (C)-(IV), (D)-(II) (A)-(III), (B)-(IV), (C)-(II), (D)-(I) |
(A)-(III), (B)-(IV), (C)-(I), (D)-(II) |
The correct answer is Option (1) → (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
Core Concept Boiling point depends on intermolecular forces like hydrogen bonding and molecular size. Detailed Explanation Compound A: $CH_3CH_2OH$ Ethanol shows intermolecular hydrogen bonding due to -OH group, giving it a relatively high boiling point around 351 K. Hence (A) matches with (III). Compound B: $CH_3OCH_3$ Dimethyl ether cannot form intermolecular hydrogen bonding. It only has dipole-dipole forces and thus has a low boiling point around 248 K. Hence (B) matches with (IV). Compound C: $H_2O$ Water forms extensive hydrogen bonding networks leading to a very high boiling point of 373 K. Hence (C) matches with (I). Compound D: $CH_3CH_2OCH_2CH_3$ Diethyl ether is larger than dimethyl ether and has stronger dispersion forces but still lacks hydrogen bonding. Its boiling point is around 348 K. Hence (D) matches with (II). |