Target Exam

CUET

Subject

Chemistry

Chapter

Inorganic: Coordination Compounds

Question:

Match List-I with List-II with the corresponding boiling points.

List-I Compound Name

List-II Boiling Point

(A) $CH_3CH_2OH$

(I) 373K

(B) $CH_3OCH_3$

(II) 348K

(C) $H_2O$

(III) 351K

(D) $CH_3CH_2OCH_2CH_3$

(IV) 248K

Choose the correct answer from the options given below:

Options:

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

(A)-(III), (B)-(IV), (C)-(II), (D)-(I)

Correct Answer:

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Explanation:

The correct answer is Option (1) → (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

List-I Compound Name

List-II Boiling Point

(A) $CH_3CH_2OH$

(III) 351K

(B) $CH_3OCH_3$

(IV) 248K

(C) $H_2O$

(I) 373K

(D) $CH_3CH_2OCH_2CH_3$

(II) 348K

Core Concept

Boiling point depends on intermolecular forces like hydrogen bonding and molecular size.

Detailed Explanation

Compound A: $CH_3CH_2OH$

Ethanol shows intermolecular hydrogen bonding due to -OH group, giving it a relatively high boiling point around 351 K.

Hence (A) matches with (III).

Compound B: $CH_3OCH_3$

Dimethyl ether cannot form intermolecular hydrogen bonding. It only has dipole-dipole forces and thus has a low boiling point around 248 K.

Hence (B) matches with (IV).

Compound C: $H_2O$

Water forms extensive hydrogen bonding networks leading to a very high boiling point of 373 K.

Hence (C) matches with (I).

Compound D: $CH_3CH_2OCH_2CH_3$

Diethyl ether is larger than dimethyl ether and has stronger dispersion forces but still lacks hydrogen bonding. Its boiling point is around 348 K.

Hence (D) matches with (II).