The angle between two diagonals of a cube is
Answer & explanation
Correct answer: option 3
$\cos \theta=\frac{-a^2+a^2+a^2}{\sqrt{a^2+a^2+a^2} \sqrt{a^2+a^2+a^2}}$ of side is a
$=\frac{1}{3}$
The angle between two diagonals of a cube is
Correct answer: option 3
$\cos \theta=\frac{-a^2+a^2+a^2}{\sqrt{a^2+a^2+a^2} \sqrt{a^2+a^2+a^2}}$ of side is a
$=\frac{1}{3}$