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A block of mass m having charge q, is hinged by a spring of spring constant k in a vertical electrostatic field E. The spring extension in equilibrium will be
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$\frac{mg}{k}$ $\frac{qE}{k}$ $\frac{mg+qE}{k}$ $\frac{mg-qE}{k}$ |
$\frac{mg-qE}{k}$ |
From the Free Body Diagram qE + kx0 = mg $x_0=\frac{mg-qE}{k}$ ∴ (D) |
