In a right-angled triangle PQR, right-angled at Q, the length of the side PR is 17 units, length of the base QR is 8 units, and length of the side PQ is 15 units. If $\angle R P Q=\alpha$, then $\sin \alpha+\cos \alpha$ is:
Answer & explanation
Correct answer: option 2
We know that,
Sinθ = \(\frac{P}{H}\)
Cosθ = \(\frac{B}{H}\)
PR = 17
QR = 8
PQ = 15
sin α + cos α
= \(\frac{8}{17}\) + \(\frac{15}{17}\)
= \(\frac{8 + 15}{17}\) =\(\frac{23}{17}\)