Four identical bulbs are connected in series with a source. These together dissipate a power P. The power dissipated, if the four bulbs are connected in parallel with the same source, will be
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 16 P
With the same source voltage \( V \), the power dissipated is \( P = V^{2}/R_{\mathrm{eq}} \), so only the equivalent resistance matters.
\( R_{\mathrm{series}} = 4R \)
\( R_{\mathrm{parallel}} = R/4 \)
\( \displaystyle \frac{P'}{P} = \frac{R_{\mathrm{series}}}{R_{\mathrm{parallel}}} = \frac{4R}{R/4} = 16 \)
\( \displaystyle P' = 16\,P \)